If two equal forces are acting at a point that makes an angle of 60 degrees between them, and the resultant force is equal to 20√3N, find the magnitude of each force.
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Let the first force =F1
And sec=F2
According to the question F1=F2
Angle=60°
Resultent (R) =20√3
Here we know,R=√(A²+B²+2ABcosT), here T=theta
So in our case,R=√(F1²+F2²+2F1F2cos60°)
So,put the all values
20√3=√(2F²+F²), because,F1=F2=F(let)and cos60°=½,so,2F²½=F²
SO,NOW,
20√3=√(3F²)
Or,20√3=√3F
Or,F=20,
SO THE EACH FORCES ARE 20N,
so,F1=F2=20N,
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