Question

If two equal magnitude (of p) forces acting at an angle of 120 degrees,their resultant is

Answer 1

The magnitude of resultant of two vectors is given by:

$R= \sqrt{A^2+B^2+2ABcosϴ}$

where θ is the angle between two vectors.

Hence,

$R= \sqrt{P^2+P^2+2P^2 \: cosϴ \: 120}$

$= \sqrt{P^2+P^2+2P^2(-0.5)} = P$

their resultant is P.