if two fair dice are rolled simultaneously what is the probability of having some of the uppermost faces either 5 or 6
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Answered by
37
Answer:
Correct option is
D
36
19
two fair dice thrown
so total cases=6×6=36
and for greater than 10 or and odd no. that mean that sum should be equal to =3,5,7,9,11,12
for getting 3=(1,2);(2,1)
for getting 5=(1,4);(4,1);(2,3);(3,2)
for getting 7=(1,6);(2,5);(3,4);(4,3);(5,2);(6,1)
for getting 9=(3,6);(4,5);(5,4);(6,3)
for getting 11=(5,6);(6,5)
for getting 12=(6,6)
so total cases=19
so probability=19/36
Answered by
1
Answer:
answer is 1/12 friends by using probability formula
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