If two forces each equal to p in magnitude at right angles their effect may be neutralised by a third force acting along their bisector in opposite direction whose magnitude is equal to
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Magnitude of the resultant of the two forces (f/2 each) = [f2/4 + f2/4 + 2. (f2/4) cos 45°]½
= (f/2).[2+2/√2]½.
= 0.9238 f.
This is the magnitude of the third force which neutralizes the effect of the two forces.
NOT SURE
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