If two forces in ratio 5:7 act on an area in the ratio 4:5.Find the ratio of pressure exerted.
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5
≡QUESTION≡
If two forces in ratio 5:7 act on an area in the ratio 4:5.Find the ratio of pressure exerted.
║⊕ANSWER⊕║
Pressure is the force act on per unit cross section area .
Pressure = force/area
Let the forces be = 5x & 7x
Let the area be = 4x & 5x
∴ P₁ = force / area
= 5x / 4x
= 5/4 Pa
P₂ = force /area
= 7x / 5x
= 7/5 Pa
∴ The ratio of P₁ and P₂ = 5/4/7/5
= 25/28
∴ The answer is 25 : 28
Answered by
3
Answer:let the area common ratio x
The area 4xand 5x
Let the common y for forces ratio
Force will be
5y and 7y
Then we know
Pr=F/A
So p1/p2=5y/4x ÷7y/5x
=5y/4x×5x/7y
=25/28 is required ratio
Explanation:
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