if two forces of 60 kN each are required to be equivalent to a single force of 60 kN, what is the angle between the forces?
Answers
Answered by
7
Using the law of parallelogram of vector addition
Which is given by
The net force = √p^2+q^2+2pqcos@
•note that all the terms are under the bracket
Thus squaring on both the sides we get
60^2 = 60^2 + 60^2 +2(60)(60)cos@
3600-7200 = 7200cos@
-3600/7200 = cos@ -1/2 which is 120 of cos function the angle will be 120°
Which is given by
The net force = √p^2+q^2+2pqcos@
•note that all the terms are under the bracket
Thus squaring on both the sides we get
60^2 = 60^2 + 60^2 +2(60)(60)cos@
3600-7200 = 7200cos@
-3600/7200 = cos@ -1/2 which is 120 of cos function the angle will be 120°
Similar questions