Question

if two forces of F1 vector equals to five hundred Newton due east and F2 vector is equals to 250 Newton due north then F2 vector minus F1 vector will be​

Answer 1

F1=500N i

F2=250 N j

therefore

-F2=250N (-j)

Fres=√F1²+F2²

=√(250000+62500)

=√(62500(4+1))

=250√5

so the resultant vector has value 250√5 and in the south east direction

Answer 2

Answer:

The subtraction of F₂ from F₁ is $-250j+500i$

Explanation:

Given that,

Force$F_{1}=-500 i\ N$

Negative sign shows the direction of first force towards west.

Another force $F_{2}=-250 j\ N$

Negative sign shows the direction of second force towards south.

We need to calculate the subtraction of F₂ from F₁

Using formula of subtraction

$F_{21}=F_{2}-F_{1}$

Put the value into the formula

$F_{21}=-250j-(-500i)$

$F_{21}=-250j+500i$

Hence, The subtraction of F₂ from F₁ is $-250j+500i$