if two gases X and Y have thier molecules travelling at velocities in the ratio of 3:1 , then the ratio of thier masses is
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Two gases X and Y have their molecules travelling at velocities in the ratio of 3:1.
We have to find the ratio of their molar masses
★ Graham's law of diffusion : Under similar conditions of temperature and pressure, rates of diffusion of different gases are inversely proportional to the square root of their molar masses.
- r ∝ 1/√M
⭆ r₁/r₂ = √M₂/√M₁
ATQ, r₁ : r₂ = 3 : 1
⭆ 3/1 = √M₂/√M₁
⭆ M₁/M₂ = (1/3)²
⭆ M₁ : M₂ = 1 : 9
Cheers!
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