Question

if two interio angles on the same side of a transversal intersecting two parallel lines are in the ratio 3:2 , then find the greater of the two angles​

Answer 1

Hello

We have

3x + 2x = 180°

5x = 180°

$x = \frac{180}{5}$

X = 36

So angles are

2 × 36 = 7 2

3 × 36 = 10 8

Answer 2

$when \: there \: is \: two \: prallel \: \: line \: and \:the \:transversal \\ \:then \:the interior \:angles \:are\: supplementary \\ \: 3ratio2 \\ \: lets \: the \: common \: multiple \: be \: x \\ 3x + 2x = 180 \\ 5x = 180 \\ x = 36 \\ \\ therefore \: 3x = 3 \times 36 = 108 \\ 2x = 2 \times 36 = 72$
So the 3x will be the greater angle
I hope it helps you
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