Question

If two interior angles of a triangle are x and 3x and the exterior angle is 96˚, then value of x :​

Answer 1

Answer:

Given -:

$\textsf{Two interior angles of the triangle = x and 3x}$

$\textsf{Exterior angle of the triangle = 96°}$

To find -:

Value of x

Taken -:

See to find value of x pr the interior angle of the triangle just use this formula -:

$\boxed{x+3x+96°=180°}$

Concept -:

Using this equation . First subtract 96° with 180° . And then divide it with the sum of x .

Solution -:

$\implies{x+3x+96°=190°}$

$\implies{4x=180°-96°}$

$\implies{4x=84°}$

$\implies{x=\dfrac{84°}{4}}$

$\implies{x=21°}$

Answer -:

So , the value of x is 21 ° .

And to find the other exterior angle of the triangle just multiply 3 with 21 .

= 21 × 3

= 63

So , the value of x is 21 ° .

And , the value of 3x is 63 ° .

Answer 2

Step-by-step explanation:

GIVEN:

TWO INTERIOR ANGLES ARE X AND 3X.

MEASURE OF EXTERIOR ANGLE OF TRIANGLE =96°.

TO FIND:

VALUE OF X.

THEOREM USED:

EXTERIOR ANGLE OF A TRIANGLE IS EQUAL TO SUM TWO OPPOSITE ANGLES.

SOLUTION;

ATQ;

X+3X=96°

=>4X=96°

=>X=96/4=24

HENCE VALUE OF X=24°.