Question

if two interior angles on the same side of a transversal intersecting two parallel lines in the ratio 2:3 ,then find the larger of two angles.

Answer 1

2:3
.: 2x+3x= 180(cointerior angle)
5x= 180
x =36
Larger angle = 3x= 3*36=108

Smaller Angle= 2x=2*36=72

Answer 2

Answer:

108° is the larger angle

Step-by-step explanation:

Explanation:

Given , a ratio of two interior angles on the same side of a transversal intersection two parallel line = 2 :3

Let the angles be 2x and 3x .

And we know that , 180° is the total interior angle sum on the same side of the transversal that intersects the two parallel lines.

Step 1:

We have one angle is 2x and the other is 3x .

2x + 3x = 180 °                [interior angles  ]

⇒5x = 180 ⇒ x =  $\frac{180}{5}$ = 36° .

So the angles are ,

 2x = 2 × 36 = 72 and

other angle is  3x = 3 × 36 = 108 .

Final answer:

Hence , larger angle is 108 °

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