Question

If two interior angles on the same side of a transversal intersecting two parallel lines are in the ratio 3:2, then find the greater of the two angles.​

Answer 1

let the angles be 3x & 2x

Answer:

3x+2x=180⁰

5x=180

x=180/5

x=36

therefore, length of greater angle is 3×36=108⁰

Answer 2

AnSwEr -:

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108 degree is the greater of the two

angle .

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Explanation-:

Given,

Two interior angles on the same side of

a transversal intersecting two parallel

lines are in the ratio 2:3

Let one angle = 2 x

Let the other angle = 3 x

As sum of interior angles on same side

of transversal intersecting two parallel

line is 180

= 2x + 3 x = 180 degree

5 x = 180 degree

x = 180/5

x= 36 degree

Hence ,

The one angle = 2x =2 x 36 = 72degree

The other angle = 3x = 3 x 36= 108

degree

Hence

the greater angle = 108 degree

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