Question

if two interior angles on the same side of a transversal intersectingtwo parallel line in the ratio 4:5 then find the smaller of two angles

Answer 1

let the angles be 4x and 5x
4x+5x = 180° [co interoir angles ]
9x = 180°
x= 180°/9
x=20°
smaller angle = 4x = 4×20° =80°

Answer 2

the sum of angles=180
4:5=4+5=9
1st angle =
$180\times \frac{4}{9}$
=80
2nd angle =
$180 \times \frac{5}{9} = 100$
the smallest angle is 80