if two interior angles on the same side of the transversal intersect in two parallel lines are in the ratio 2 : 3 then find the angles
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Step-by-step explanation:
Since, the interior angles are in the ratio of 2:3.
So, Let the two interior angles be "2x" and "3x" respectively.
Since, the two int. angles are on the same side of transversal.
So, 2x + 3x = 180° (co-interior angles)
=> 5x = 180°
Therefore, x = 180°/5
= 36°
So, 1st angle = 2x
= 2 × 36°
= 72°
And, 2nd angle = 3x
= 3 × 36°
= 108°
Hope it helps :)
Answered by
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Two interior angles on the same side of a transversal intersecting two parallel lines are in the ratio 2:3 ....(Given)
Let one angle = 2x
Other angle = 3x
As sum of interior angles on same side of transversal intersecting two parallel line is 180
⇒2x = 3x = 180
⇒5x = 180
⇒x = 180 / 5 =36
Hence, two angles are 2x = 2 × 36 = 72
⇒3x = 3 × 36 = 108
Hence, greater angle is 108
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