If two intersecting chord of a circle make equal angles with the diameter passing through their points of intersecting prove that the chord are equal
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It is given that two intersecting chords (AP and AQ) of a circle make equal angles with the diameter passing through their point of intersection A, therefore∠PAB=∠QAB. ... So, have the two chords AP and AQ equal, since they are equidistant from the centre of the circle. Hence proved.
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