Question

If two intersecting chords of a circle make equal angles with the diameter
passing through their point of intersection, prove that the chords are equal.
​

Answer 1

Let AB and CD be the two chords.

Construct OM AB and ON CD

In OME and ONE,

1 = 2        (given)

OME = ONE = 90o

OE = OE          (common)

By AAS congruence rule,

OM = ON        (c.p.c.t)

Hence, AB = CD

(Since, chords equidistant from the centre are equal)

 

 

Answer 2

Answer:

Here is the answer

Step-by-step explanation:

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