if two intersecting circles have a common chord of length 16 cm and if the radii of two circles are 10 cm and 17 cm find the distance between their centres
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Answered by
37
A perpendicular from the centre to a chord bisects the chord
So ca=16/2=8
In oac
10^2-8^2=oc^2
√36=oc
6=oc
Similiarly
in pca
Pc=15
Therefore
Total distance bw the centres=15+6=21....
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Answer:
Step-by-step explanation:
A perpendicular from the centre to a chord bisects the chord
So ca=16/2=8
In oac
10^2-8^2=oc^2
√36=oc
6=oc
Similiarly
in pca
Pc=15
Therefore
Total distance bw the centres=15+6=21....
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