if two isosceles triangles have a common base, prove that the line joining their vertices bisects them at right angles.
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Too prove=AD bisects BBC at right angles<br> Proof=2N<br> AB=AC(given)<br> BD=CD(given)<br> BC=BC(common)<br><br><br><br> AB=AC<br><br> AE=AE(common)<br><br> BE=CE<br><br><br><br>.
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