If two isosceles triangles have equal bases and equal vertical angles.prove that they are congurent
Answers
Answered by
1
Answer:
just use A.S.A Congruence theory
Answered by
1
Answer:
Given two triangles ABC and DEF.
Given that vertex angle= ⎳BAC = ⎳EDF= θ
BC = EF = a
Let AB = BC = m ; DE=EF = n
Applying Cosine rule in ∆ABC,
a²= m²+m²-2(m)(m) cos θ
a²= 2m²-2m² cos θ
a²= 2m²(1-cos θ) ——(1)
Similarly, in ∆DEF,
a²= 2n²(1-cos θ) ——(2)
From .eqn (1) and (2),
2m²(1-cos θ)= 2n²(1-cos θ)
m² = n²
m = n
AB = DE and AC= DF
Their included angle θ is same (given)
If two sides and the included angle of a triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.
∴ ∆ ABC ≅ ∆DEF
Step-by-step explanation:
I hope it helps please mark me as brainliest
Attachments:
Similar questions
English,
9 days ago
Computer Science,
18 days ago