If two legs of a right angle triangle are equal and the hypotenuse measure 64 cm, find the length of leg.
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Answered by
3
(base)2 + (height)2 = 64
(x)2 + (x)2 = 64
2x square = 64
(x)2 = 64/2
(x)2 = 32
x = 4underroot2
(x)2 + (x)2 = 64
2x square = 64
(x)2 = 64/2
(x)2 = 32
x = 4underroot2
kartikeyasingh:
how
Answered by
1
Let the length of two legs be a cm.
a^2+a^2=64^2
a^2+a^2=4096
2a^2=4096
a^2=4096/2
a^2=2048
a=√2048
a=45.25 Answer
a^2+a^2=64^2
a^2+a^2=4096
2a^2=4096
a^2=4096/2
a^2=2048
a=√2048
a=45.25 Answer
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