if two legs of a right triangle are equal and the hypotenuse measures 64 cm find the length of each leg
Anonymous:
Do you think it should be the 'Square of hypotenuse measures 64 cm'
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Solution :-
Let ABC be the triangle.
Then,
AB is the hypotenuse, BC is the perpendicular and AC is the base and BC and AC are of equal length.
Let BC = AC = x
Then, applying Pythagoras Theorem.
(Hypotenuse)² = (Perpendicular)² + (Base)²
⇒ (AB)² = (BC)² + (AC)²
⇒ (64)² = (x)² + (x)²
⇒ 4096 = 2(x)²
⇒ (x)² = 4096/2
⇒ (x)² = 2048
⇒ x = √2048
⇒ x = 45.254 cm
So, length of each side is 45.254 cm
Answer.
Let ABC be the triangle.
Then,
AB is the hypotenuse, BC is the perpendicular and AC is the base and BC and AC are of equal length.
Let BC = AC = x
Then, applying Pythagoras Theorem.
(Hypotenuse)² = (Perpendicular)² + (Base)²
⇒ (AB)² = (BC)² + (AC)²
⇒ (64)² = (x)² + (x)²
⇒ 4096 = 2(x)²
⇒ (x)² = 4096/2
⇒ (x)² = 2048
⇒ x = √2048
⇒ x = 45.254 cm
So, length of each side is 45.254 cm
Answer.
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