if two line are perpenduvular l1=x+(a-1)y=1 and l 2 =2x+a^2y=1 then find the value of a
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If the lines are perpendicular, then (-1/a-1)(-2/a^2) =-1
2=-(a^3 - a^2)
a^3 - a^2 +2=0
a=-1
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