If two lines AB, CD are perpendicular to the same line EF then AB and CD are
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Step-by-step explanation:
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Let BD= a and DF=b.
In △ABF, CD∥AB
ABCD=BFDF i.e.,
xz=a+bb....(I)
And, in ΔBEF, CD is parallel to EF
⇒EFCD=BFBD i.e.
yz=a+ba...(II)
Adding I and II
∴xz+yz=a+bb+a+ba=1
⇒x1+y1=z1
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Answer:
perpendicular lines
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