if two lines are parallel then prove that any pair of bisected of their alternate interior angle is also parallel.
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GIVEN AB∣∣CD are cut by a transversal t at E and F respectively, EG and FH are the bisectors of a pair of alt. int. ∠s,∠AEF and anl≥EFD respectively.
TO PROVE EG∣∣FH,
PROOF Since AB∣∣CD and t is a transversal, we have :
∠AEF=∠EFD [alt. int. ∠s]
⇒12∠AEF=12∠EFD
⇒∠GEF=∠EFH.
But, these are alternate interior angles formed when the transversal EF cuts EG and FH.
∴EG∣∣FH.
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