Question

If two liquids drops of same density but of masses m and 27m fall simultaneously in a viscous medium with terminal speed v and nv then value of n is

Answer 1

Answer:

n=9.

Explanation:

We know that the terminal velocity v is directly proportional to the radius^2. Since, the mass of the sphere is given as volume*density which is 4/3πR^3*density from where we get that mass is directly proportional to the R^3. So, from the question we get that the masses are m and 27m. Hence, according to the equation we will be getting that 1/27=(R1/R2)^3 which on solving we will get R2=3R1.

Since, terminal velocity v1/v2=(R1/R2)^2 which is v1/v2 = 1/9. Since, from the question we get that v1=v and v2=nv. So, on solving we will get the value of n as 9.

Answer 2

Explanation:

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