Math, asked by lukeshluha, 1 year ago

if two ludo-dice are thrown once then what is the probability of getting 9 as the sum of the two numbers shown by both the dice?

Answers

Answered by Shivamind
1
The probability is 4/36 i.e. 1/9
Answered by RvChaudharY50
0

Question :- If two balanced dice are tossed once, what is the probability of the event that the sum of the integers coming on the upper sides of the two dice is 9 ?

Solution :-

we know that, when two dice are tossed once, then possible events will be

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

  • Total 36 .

so,

→ Total possible events where sum of upper side of the dice is 9 is = (3,6), (4,5), (5,4) and (6,3) = Total 4 .

therefore,

→ Required Probability = Favourable outcomes / Total number of outcomes = 4/36 = (1/9) (Ans.)

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