Question

If two masses ‘X’ kg and 200kg are at a distance of 20m and gravitational force of attraction between them is 3.335x10-9N, calculate the value of ‘X’.

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Answer 1

Answer:

Let the masses be = M1 and M2 respectively

M1 = X kg and M2 = 200 kg

Having in mind that;

G = 6.67 x 10^-11 Nm^2kg^-2       R = 20 m     F = 3.335 x 10^9 N

From the Universal Law of Gravitation; F = G M1M2

                                                                         R^2  

We obtain;

X = F.R^2

      G.M2

X  = (3.335 x 10^9 N).[(20 m )^2]

  (6.67 x 10^-11 Nm^2kg^-2).(200 kg)

:.X = (1.334 x 10^12 Nm^2)

     (1.334 x 10^-8 Nm^2kg^-1)  

X = 1 x 10^20 kg

         

Explanation: