Question

if two moles of an ideal gas at 540 k is 44.8 litres than its pressure is?

Answer 1

Explanation:

Hello! Let me try to answer this ^ ^

p = \frac{n.R.T}{V}p=

V

n.R.T

= \frac{(2)(0.082)(546)}{44.8}=

44.8

(2)(0.082)(546)

= 1.99875 atm=1.99875atm

= 2 atm=2atm

Thanks, please correct if there are any mistakes :)