Question

If two moles of an ideal monatomic gas at temperature t are mixed with 4 moles of ideal diatomic gas at temperature to t then the temperature of mixture is

Answer 1

Explanation:

If two moles of an ideal monatomic gas at temperature t are mixed with 4 moles of ideal diatomic gas at temperature to t then the temperature of mixture is

Answer 2

Answer:

RT

Explanation:

Missing point in question :- Find out the amount of heat to dissociate 2 moles of the gas into atoms at the same temperature?

E(Internal Energy) =  (f/2 x RT)

for monoatomic gas - f = 3

for diaatomic gas - f =5

When it combines, heat amount Q = △E

Q = E_f - E_i

where,

E_i = diatomic gas  internal energy

E_f =  monoatomic gas + diatomic gas internal energy  

E_i = 4 x 5/2 RT = 10 RT

E_f = 4 x 3/2 RT + 2 x 5/2 RT

= 6 RT + 5 RT

= 11 RT

Q = △E = E_f - E_i  

=  11 RT - 10 RT  

Q = RT