If two moles of an ideal monatomic gas at temperature t are mixed with 4 moles of ideal diatomic gas at temperature to t then the temperature of mixture is
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Explanation:
If two moles of an ideal monatomic gas at temperature t are mixed with 4 moles of ideal diatomic gas at temperature to t then the temperature of mixture is
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Answer:
RT
Explanation:
Missing point in question :- Find out the amount of heat to dissociate 2 moles of the gas into atoms at the same temperature?
E(Internal Energy) = (f/2 x RT)
for monoatomic gas - f = 3
for diaatomic gas - f =5
When it combines, heat amount Q = △E
Q = E_f - E_i
where,
E_i = diatomic gas internal energy
E_f = monoatomic gas + diatomic gas internal energy
E_i = 4 x 5/2 RT = 10 RT
E_f = 4 x 3/2 RT + 2 x 5/2 RT
= 6 RT + 5 RT
= 11 RT
Q = △E = E_f - E_i
= 11 RT - 10 RT
Q = RT
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