Question

If two normal dice are thrown together,
what is the probability of getting a sum of 6​

Answer 1

Answer:

(1,5) (2,4) (3,3) (4,2) (5,1)

as we know that dice is thrown twice

Therefore total outcome will be 36

p(E) = favorable outcome / total outcome

p(E)=5/36

Answer 2

Answer:

5/36

Step-by-step explanation:

When 2 dices are rolled

N(s) = 36

Let A be event of getting sum 6

Then A = {3,3}{2,4}{4,2}{1, 5}{5, 1}

•°• N(A) = 5

•°• probability = n(a) /n(s)

= 5/36