Question

if two normal dice are thrown together what is the probability of getting a sum of 6​

Answer 1

Answer:

the probability of getting a sum of 6

= getting a sum of 6/ number of dice

= (1,5)(2,4)(3,3)(5,1)(4,2)(3,3)/2

= 6/2

= 3/1

Answer 2

Answer:

5/36

Step-by-step explanation:

Number of outcomes= 36 n(s)

Number of outcomes having sum of 6;

(1,5) (2,4) (3,3)(4,2)(5,1) = 5 n(E)

P(E) = n(E)/n(s)

=5/36