if two numbers are in the ratio of 2:3 if 2 is the digit at units place and 3 at tens place. if you add 27 to it the digits interchange
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hii mate!!
Let the digits of number be x and y, with x being tens digit and y the other.
So, our number is= 10x + y
Now, we are given the ratio
x/y = 2/3
Now, 27 is added to number and number reverses digits,so
10x + y + 27 = 10y + x
9x - 9y = -27....(1)
Now, we know x/y = 2/3
or we can say 3x = 2y
or, 9x = 6y....(2)
Putting this value in (1) we get
6y - 9y = -27
-3y = -27
y = 9
So, x = 2/3 * y = 2/3 * 9 = 6
Our number is 69
hope it helps !!☺☺☺☺
Let the digits of number be x and y, with x being tens digit and y the other.
So, our number is= 10x + y
Now, we are given the ratio
x/y = 2/3
Now, 27 is added to number and number reverses digits,so
10x + y + 27 = 10y + x
9x - 9y = -27....(1)
Now, we know x/y = 2/3
or we can say 3x = 2y
or, 9x = 6y....(2)
Putting this value in (1) we get
6y - 9y = -27
-3y = -27
y = 9
So, x = 2/3 * y = 2/3 * 9 = 6
Our number is 69
hope it helps !!☺☺☺☺
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