Question

If two numbers are respectively 20% and 50% of a third
number, what is the percentage of the first number to the
Second​

Answer 1

Answer:

let third number x

Step-by-step explanation:

than first no

x of 20/100

x/5

than second no

x of 50/100

x/2

than the % of first number to second is

(x/5×100)/x/2

20x×2/x

40 % ok

Answer 2

$\mathfrak{\large{\underline{\underline{Answer:}}}}$

The percentage of First number to second Number is 40%.

$\mathfrak{\large{\underline{\underline{Step-by-step\: explanation}}}}$

$\textsf{\underline{\underline{Given : }}}$

$\textsf{First number is = 20\% of third}$

$\textsf{Second number is = 50\% of third}$

$\textsf{\underline{\underline{To find :}}}$

$\textsf{Percentage of the first number to the Second}$

$\textsf{\underline{\underline{Solution :}}}$

$\textsf{Let the third number be as y}$

$\textbf{\small{\underline{First Number - }}}$

$\sf{\longrightarrow} \: 20\% \: of \: y \\ \\ \sf{\longrightarrow} \: \frac{20}{100} \times y \\ \\ \sf{\longrightarrow} \: \frac{20y}{100} \: .....{\rm{\gray{ \: (First \: Number)}}}$

$\rule{300}{1.5}$

$\textbf{\small{\underline{Second Number -}}}$

$\sf{\longrightarrow} \: 50\% \: of \: y \\ \\ \sf{\longrightarrow} \: \frac{50}{100} \times y \\ \\ \sf{\longrightarrow} \: \frac{50y}{100} \: ......\rm{\gray{(Second \: Number)}}$

$\rule{300}{1.5}$

$\textsf{Percentage of First number to second Number -}$

$\sf{\longrightarrow} \: \dfrac{First \: Number}{Second \: Number} \times 100 \\ \\ \sf{\longrightarrow} \: \left(\dfrac{ \frac{20y}{100}}{ \frac{50y}{100}}\right) \times 100 \\ \\ \sf{\longrightarrow} \: \left(\frac{20y}{\cancel{100}} \times \frac{\cancel{100}}{50y}\right) \times 100 \\ \\ \sf{\longrightarrow} \: \frac{2y}{5y} \times 100 \\ \\ \sf{\longrightarrow} \: \frac{200y}{5y} \\ \\ \sf{\longrightarrow} \: 40\%$

$\therefore$ The percentage of First number to second Number is 40%.