If two-numbers are respectively 3 0% and 40% less than a number, then what percent of second number less than
first one?
a) 35% b) 362%
c) 14% d) 142%
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let the third number be x
therefore first number = x - 30x/100
= (100x - 30x)/100 = 70x/100 = 7x/10
second number = x - 40x/100
= (100x - 40x) /100 = 60x/100 = 6x/10
Required ℅ 6x/10/7x/10*100
= 6x/10 * 10/7 * 100 = 600/7 = 85.5/7
hope it helps you.
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