if two numbers are respectively 30%and40% more than a third number, what percent is the first of the second?
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10% thats my answer 5 star plss
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Two numbers are respectively 30% and 40% less than a third numbers
Let the third number be =x.
So, First no. =x−30%of=
10
7x
And, Second No. = x−40%=
10
8x
Percent of second number less than of the first number =
10
7x
10
7x
−
10
6x
∗100=
10
7x
10
x
∗100=
7
100
=14.2857≈14.29%
Therefore,
Percent of second number is 14.29% less of the first number. So
Percent second of the first =100%−14.29%=85.71%
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