Math, asked by ratnesh3027, 1 year ago

.
If two of the roots of equation x4 - 2x3 + ax2 + 8x + b = 0 are equal in magnitude but opposite in sig
then value of 4a + b is equal to :
(A) 16
(B) 8
(C) -16
theme values are also
28 ** ** *5 = o are equal in magnitude but opposite in
(D) -8​

Answers

Answered by MaheswariS
25

\textbf{Given:}

\text{Two of the roots of $x^4 - 2x^3 +ax^2+8x+b=0$ are equal but opposite in magnitude}

\textbf{To find:}

\text{The value of $4a+b$}

\textbf{Solution:}

\text{Let the roots of $x^4 - 2x^3 +ax^2+8x+b=0$ be $m,-m,n$ and $p$}

\text{Then,}

S_1=m+(-m)+n+p=2

\implies\bf\,n+p=2.......(1)

S_3=-m^2n-mnp+mnp-pm^2=-8

\implies\,-m^2n-pm^2=-8

\implies\,-m^2(n+p)=-8

\text{Using (1), we get}

\implies\,m^2(2)=8

\implies\,m^2=4

\implies\,m=\pm\,2

\text{Thus, we have 2 and -2 are two roots of the given equation}

\text{Since 2 is a root of $x^4 - 2x^3 +ax^2+8x+b=0$, 2 satisfies the equation}

2^4-2(2)^3+a(2)^2+8(2)+b=0

16-16+4\,a+16+b=0

4\,a+16+b=0

\implies\boxed{\bf\,4\,a+b=-16}

\therefore\textbf{The value of 4a+b is -16}

\implies\textbf{Option (C) is correct}

Find more:

If a,b,c are rational then the root of equation (a+2b-3c )x²+(b+2c-3a)x+ (c+2a-3b)=0

https://brainly.in/question/4813981

Given that a=alpha and b=beta are roots of 2x^2+x+14=0 find the equation whose roots are a^4 and b^4

https://brainly.in/question/17088379

Answered by ayush778751
1

Answer:

(c) -16 is correct answer

Please make Brainlist.

Similar questions