If two of the zeroes of the cubic polynomial ax^3 + bx^2 +cx + d are 0 (zero) then the third zero is :
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16
Step-by-step explanation:
let third zero =x
sum of zeros = -b/a
0+0+x= -b/a
hence
x= -b/a
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Answered by
0
Answer: -b/a
Step-by-step explanation:
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