If two of the zeroes of the polynomial
X3+2x2-x-2 are 1 and -1, then find the other zero of the polynomial. *
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Step-by-step explanation:
given two zeroes = 1 and -1
it means it will be( x+1)(x-1) =0
= x^-1 ( as the above eq is in the form of (a+b) (a-b)= a^2-b^2)
divide the main eq x³+2x²-x-2 by x²-1 u will get the quotient and the remainder
solve the eq by divident = divisor× quotient + remainder
u will get the rest two zeroes
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