Question

If two of the zeroes of the polynomial x4 + 3x3 – 7x2 – 27x – 18 are – 1 and – 2, find the other zeroes.​

Answer 1

Answer:

The other two factors are

3 and (-3)

Step-by-step explanation:

Explanation in attachment⬆️⬆️⬆️⬆️

Hope it helps❤️

Answer 2

Step-by-step explanation:

dividend x4 - 3x3 - 7x2 + 27x - 18

- divisor. * x3 x4 - 3x3

remainder - 7x2 + 27x - 18

- divisor * 0x2

remainder - 7x2 + 27x - 18

- divisor * -7x1 - 7x2 + 21x

remainder 6x - 18

- divisor * 6x0 6x - 18

remainder 0

Quotient : x3-7x+6 Remainder: 0