if two of the zeros of P(x) = 5 x power 4 - 5 x power 3 -33 x power 2 + 3x-2 root of 3 by 5 and - root 3 by 5 find the other two zeros
Anonymous:
Please mention roots again whether it is √(3/5) or √3/5
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a) Zeros of the polynomial :
5x^4-5x^3-33x^2+3x-2=0. (1)
are√3/5 & -√3/5 . (given)
b) Sum of roots of a bi-quadratic polynomial
ax^4+bx^3+cx^2+dx+e=0 is given by
-b/a .
Product of roots = e/a.
c) Let α & β be two other roots of equation :(1)
.
Now,
Sum of roots = -(-5)/5 = 1
√3 / 5 + (-√3/5) + α + β = 1
α+β =1
Product of roots = (-2)/5
α*β*(√3/5)*(-√3/5)= -2/5
α*β = 10/3
Now, here you have product of roots and sum of roots .
d) Make quadratic equation and use quadratic formula to find α and β .
QE is x^2- x+10/3.
x = (1+√1-40/3)/ 2 or (1-√1-40/3)/2.
5x^4-5x^3-33x^2+3x-2=0. (1)
are√3/5 & -√3/5 . (given)
b) Sum of roots of a bi-quadratic polynomial
ax^4+bx^3+cx^2+dx+e=0 is given by
-b/a .
Product of roots = e/a.
c) Let α & β be two other roots of equation :(1)
.
Now,
Sum of roots = -(-5)/5 = 1
√3 / 5 + (-√3/5) + α + β = 1
α+β =1
Product of roots = (-2)/5
α*β*(√3/5)*(-√3/5)= -2/5
α*β = 10/3
Now, here you have product of roots and sum of roots .
d) Make quadratic equation and use quadratic formula to find α and β .
QE is x^2- x+10/3.
x = (1+√1-40/3)/ 2 or (1-√1-40/3)/2.
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