Question

if two opposite Angeles of a parallelogram are ( 63-3x ) degree and ( 4x-7) degree. find all angles of parallelogram

Answer 1

We know that,

Opposite angles of paralellogram are equal

=> 63-3x = 4x - 7

=> 63 + 7 = 4x +3x

=> 7x = 70

=> x = 10

First angle = 33°

Second angle = 180 - 33 = 147°

Third angle = 33°

Fourth angle = 147°

Answer 2

opposite angles of parallelogram are equal.
Therefore, 63-3x= 4x-7
63+7=4x+3x
70=7x
x=10
therefore, angles are 4(10)-7= 40-7=33°s
and 180-33=147°s