Question

if two opposite angle of a parallelogram are (63-3x) and (4x-7) find all the angle of the parelelogram

Answer 1

Opposite angles of a parallelogram are congruent
$63 - 3x = 4x - 7 \\ 63 + 7 = 4x + 3x \\ 70 = 7x \\ x = \frac{70}{7} \\ x = 10$
therefore,
$63 - 3x \\ 63 - (3 \times 10) \\ 33 \\ 4x - 7 \\ 4 \times 10 - 7 \\ 33$
the sum of adjacent angles of a parallelogram is 180°.
33+y=180
y=147°
Therefore, Angles of parallelogram are 33°,147°,33°,147°.
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