If two opposite angle of a parallelogram are (63 - 3x) degre and (4x - 7) degree ,find the angle of a parallelogram.
Answers
Answered by
2
We know that Opposite angles of paralellogram are equal.
So,
63 - 3x = 4x - 7
=> 63 + 7 = 4x + 3x
=> 7x = 70
=> x = 10
First angle = (63 - 3× 10) = 63 - 30 = 33°
Second angle = 180 - 33 = 147°
Third angle = 33°
Fourth angle = 147°
So,
63 - 3x = 4x - 7
=> 63 + 7 = 4x + 3x
=> 7x = 70
=> x = 10
First angle = (63 - 3× 10) = 63 - 30 = 33°
Second angle = 180 - 33 = 147°
Third angle = 33°
Fourth angle = 147°
Answered by
0
Step-by-step explanation:
63 - 3x = 4x - 7
=> 63 + 7 = 4x + 3x
=> 7x = 70
=> x = 10
1st angle = (63 - 3× 10) = 63 - 30 = 33°
2nd angle = 180 - 33 = 147°
3rd angle = 33°
4th angle = 147°
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