Question

if two opposite angles of a parallelogram are (63 - 3x)° and(4 x-7)°. find all the angles of the parallelogram

Answer 1

Hope it helps

Given-----_

angles are (63 - 3x) and (4x - 7).

We know that opposite angles of a parallelogram are equal.

(63 - 3x) = (4x - 7)

-3x = 4x - 70

-7x = -70

x = 10.

Therefore the angles of a parallelogram are,

63 - 3x = 63 - 3(10)

             = 63 - 30

             = 33.

We know that sum of adjacent angles is 180 = 180 - 33

                                                                           = 147.


4x - 7 = 4(10) - 7

          = 40 - 7

          = 33.


We know that Sum of adjacent angles is 180 = 180 - 33

                                                                            = 147.


Therefore the angles of a parallelogram = 33,147,33,147

Answer 2

We know opposite angles of a parallelogram are equal.
A/Q; we have
(63 -3x)=(4x-7)
Therefore; x=10
Angles are respectively are; 33;33;147 and 147.