If two opposite angles of a parallelogram are (63 − 3x)° and (4x − 7)°. Find all the angles of the parallelogram.
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2
Answer:
Your answer is 45
Your answer is 49
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Answer:
So,
(63-3x)° = (4x-7)°
=> -3x-4x = -7 -63
=> -7x = -70
=> 7x = 70
=> x = 70/7 = 10
Now,
(63-3x)° = 63-30 = 33°
and (4x-7) = 40-7 = 33°
Now,
Let, other two angles = x (as they are equal )
x+x+33+33 = 360
=> 2x +66 = 360
=> 2x = 360-66
=> 2x = 294
=> x = 294/2= 147
Hence,
All angles = 33°,147°,33° and 147°.
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