If two opposite angles of a parallelogram are (63 -3x)° and (4x -7)°. Find all the angles of the parallelogram.
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Answered by
8
as we know that opposite anhles in a parallelogram are equal.
so,
63-3x=4x-7
=>70=7x
=>x=10
so 2 angles of the parallelogram are 33°,33°.
sum of alternate angles in a parallelogram is 180° .
using this,
angle1+33°=180°
=>angle =147°
so the other 2 angles are 147° each.
so,
63-3x=4x-7
=>70=7x
=>x=10
so 2 angles of the parallelogram are 33°,33°.
sum of alternate angles in a parallelogram is 180° .
using this,
angle1+33°=180°
=>angle =147°
so the other 2 angles are 147° each.
prafullika2005:
Here is what i got with all proper statement.
Answered by
31
▶ Given :-
→ Two opposite angles of a parallelogram are (63 -3x)° and (4x -7)°
▶ To find :-
→ All the angles of ||gm .
We know that, the opposite angles of ||gm are equal .
°•° 63 - 3x = 4x - 7 .
==> 63 + 7 = 4x + 3x .
==> 7x = 70 .
==> x = 70/7 .
•°• x = 10 .
→ 63 - 3x = 63 - 3 × 10 .
= 63 - 30 .
= 33 .
Hence, 2 opposite angles are equal i.e., 33° .
And, also adjacent angles of ||gm are co- interior angles .
Let two other angles [ they were equal as opposite angles of ||gm ] of ||gm be y° .
°•° 33 + y = 180 .
==> y = 180 - 33 .
•°• y = 147° .
✔✔ Hence, all angles of ||gm are 33°, 33°, 147°, 147° ✅✅ .
THANKS
#BeBrainly.
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