Math, asked by yashchauhan1965, 1 year ago

If two opposite angles of a parallelogram are (63 -3x)° and (4x -7)°. Find all the angles of the parallelogram.

Answers

Answered by priyanshu1812
8
as we know that opposite anhles in a parallelogram are equal.
so,
63-3x=4x-7
=>70=7x
=>x=10

so 2 angles of the parallelogram are 33°,33°.

sum of alternate angles in a parallelogram is 180° .
using this,
angle1+33°=180°
=>angle =147°
so the other 2 angles are 147° each.

prafullika2005: Here is what i got with all proper statement.
adityayuren62: thx bro
Answered by Anonymous
31
 \huge \bf \orange{ Hey \: there }

▶ Given :-

→ Two opposite angles of a parallelogram are (63 -3x)° and (4x -7)°

▶ To find :-

→ All the angles of ||gm .

 \huge \pink{ \sf Solution :- }

We know that, the opposite angles of ||gm are equal .

°•° 63 - 3x = 4x - 7 .

==> 63 + 7 = 4x + 3x .

==> 7x = 70 .

==> x = 70/7 .

•°• x = 10 .

→ 63 - 3x = 63 - 3 × 10 .

= 63 - 30 .

= 33 .

Hence, 2 opposite angles are equal i.e., 33° .

And, also adjacent angles of ||gm are co- interior angles .

Let two other angles [ they were equal as opposite angles of ||gm ] of ||gm be y° .

°•° 33 + y = 180 .

==> y = 180 - 33 .

•°• y = 147° .

✔✔ Hence, all angles of ||gm are 33°, 33°, 147°, 147° ✅✅ .

THANKS

#BeBrainly.
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