if two opposite angles of a parallelogram are 63-3x° & 4x - 7° find all the angles of the parallelogram
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In a parallelogram, the opposite angles are equal.
Here, the opp angles are 63°-3x° and 4x°-7°.
=> 63°-3x° = 4x°-7°
-3x°-4x°=-7°-63°
-7x°=-70°
x=70÷7
x=10°
Substituting x in both, we get:
63°-3x°= 63°-3(10°)
=63°-30°
=33°
Therefore, two angles are 33°.
In a parallelogram, the adjacent angles are supplementary.
=> 33°+y=180°
y=180°-33°
y=147°.
Therefore , the other two angles are 147°.
Here, the opp angles are 63°-3x° and 4x°-7°.
=> 63°-3x° = 4x°-7°
-3x°-4x°=-7°-63°
-7x°=-70°
x=70÷7
x=10°
Substituting x in both, we get:
63°-3x°= 63°-3(10°)
=63°-30°
=33°
Therefore, two angles are 33°.
In a parallelogram, the adjacent angles are supplementary.
=> 33°+y=180°
y=180°-33°
y=147°.
Therefore , the other two angles are 147°.
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