If two parallel chords of the circle having diameter 4 units lie on the opposite sides
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Answer:
cos2Q=1/7
=2cos2Q−1=1/7
=2cos2Q=8/7
cos2Q=74
=4cp12=74
=cp1=74
sec2Q=7=2cos2Q−11=7
=2(2cp2)2−1=71
=2(2cp2)2=78
=cp2=74=74+74
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Step-by-step explanation:
distance between chords
= Radius Cos(subtended angle/2) by chord1 + Radius Cos(subtended angle/2) by chord 2
Radius = Diameter /2 = 4/2 = 2
= 2 Cos (0₁1/2) + 2Cos(0₂/2)
0₁ = Cos-¹(1/7) => Cos0₁ = 1/7
0₂ = Sec-¹7 => Sec0₂ = 7 => 1/Cos0₂ = 7 => Cos0₂ = 1/7
Applying Cos20 = 2Cos²0 - 1=> Cos²0 = (1 + cos20)/2
Putting 0₁/2 =
Cos (0,₁/2) = (1+1/7)/2 = 4/4
=> Cos(0₁/2) = 2/√7
Putting 0 = = 0₂/2
Cos (0₂/2) = (1+1/7)/2 = 4/7
=> Cos(0₁/2) = 2/√7
2 Cos (0₁/2) +2Cos(0₂/2) = 2 *2/√7 + 2* 2/√7
= 4/√7 + 4/√7
= 8/√7
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