Math, asked by roseglair22, 1 year ago

if two parallel lines are intersected by a transversal prove that the bisectors of two pairs of interior angles form a rectangle​

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Answered by fish2003
0

Step-by-step explanation:

(To prove any quadrilateral a parallelogram or one of its type, square, rhombus,etc ,for this remember the properties of all types of quadrilateral and prove that the quadrilateral satisfies these and hence done.) here, the quadrilateral whose all angles is 90° is a rectangle.

The sum of angles in a straight line is 180°. Here the number of angles that make it us 2. The sum bisectors of the angles is( 1÷2).180° =90° This gives one angle of quadrilateral formed. Now sum of co- interior angles is also 180 ° the angle formed by bisectors is [1/2.]180=90° . parallely, all angles will be 90°.

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