If two parallel lines are intersected by a transversal, show that the bisectors of any corresponding angles are parallel
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Answer:
Given: AB and CD are two parallel lines and transversal EF intersects then at G and H respectively. GM and HN are the bisectors of two corresponding angles ∠EGB and ∠GHD respectively.
To prove: GM∥HN
Proof:
∵AB∥CD
∴∠EGB=∠GHD (Corresponding angles)
⇒21∠EGB=21∠GHD
⇒∠1=∠2
(∠1 and ∠2 are the bisector of ∠EGB and ∠GHD respectively)
⇒GM∥HN
(∠1 & ∠2 are corresponding angles formed by transversal GH and GM and HN and are equal.)
Hence, proved.
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